Tiffany started jogging from the farm to the park at a speed of 110 m/min at 6 a.m. Her cousin started jogging from the farm later. They were beside each other at 6.32 a.m. and her cousin reached the park at 7 a.m. while Tiffany was still 1400 m away. If both of them travelled at a constant speed throughout the journey, what time did her cousin leave the farm?
1 h = 60 min

From 6 a.m. to 7 a.m. = 1 h
From 6.32 a.m. to 7 a.m. = 28 min

Distance between the farm and the park
= 60 x 110 + 1400
= 6600 + 1400
= 8000 m

Distance that Tiffany's cousin had to cover to catch up with Tiffany
= 32 x 110
= 3520 m

Distance that Tiffany's cousin travelled to the park after catching up with Tiffany
= 8000 - 3520
= 4480 m

Since Tiffany's cousin jogged 4480 m in 32 min,
Tiffany's cousin average speed
= 4480 ÷ 28
= 160 m/min

Duration that Tiffany's cousin took to jog to the park
= 8000 ÷ 160
= 50 min

Time that Tiffany's cousin left the farm:
50 min before 7 a.m. = 6.10 a.m.

Answer(s): 6.10 a.m.