Wendy started jogging from the mosque to the park at a speed of 96 m/min at 5 a.m. Her cousin started jogging from the mosque later. They were beside each other at 5.35 a.m. and her cousin reached the park at 6 a.m. while Wendy was still 1600 m away. If both of them travelled at a constant speed throughout the journey, what time did her cousin leave the mosque?
1 h = 60 min

From 5 a.m. to 6 a.m. = 1 h
From 5.35 a.m. to 6 a.m. = 25 min

Distance between the mosque and the park
= 60 x 96 + 1600
= 5760 + 1600
= 7360 m

Distance that Wendy's cousin had to cover to catch up with Wendy
= 35 x 96
= 3360 m

Distance that Wendy's cousin travelled to the park after catching up with Wendy
= 7360 - 3360
= 4000 m

Since Wendy's cousin jogged 4000 m in 35 min,
Wendy's cousin average speed
= 4000 ÷ 25
= 160 m/min

Duration that Wendy's cousin took to jog to the park
= 7360 ÷ 160
= 46 min

Time that Wendy's cousin left the mosque:
46 min before 6 a.m. = 5.14 a.m.

Answer(s): 5.14 a.m.