Eva started jogging from the boutique to the garden at a speed of 114 m/min at 5 a.m. Her cousin started jogging from the boutique later. They were beside each other at 5.35 a.m. and her cousin reached the garden at 6 a.m. while Eva was still 1900 m away. If both of them travelled at a constant speed throughout the journey, what time did her cousin leave the boutique?
1 h = 60 min

From 5 a.m. to 6 a.m. = 1 h
From 5.35 a.m. to 6 a.m. = 25 min

Distance between the boutique and the garden
= 60 x 114 + 1900
= 6840 + 1900
= 8740 m

Distance that Eva's cousin had to cover to catch up with Eva
= 35 x 114
= 3990 m

Distance that Eva's cousin travelled to the garden after catching up with Eva
= 8740 - 3990
= 4750 m

Since Eva's cousin jogged 4750 m in 35 min,
Eva's cousin average speed
= 4750 ÷ 25
= 190 m/min

Duration that Eva's cousin took to jog to the garden
= 8740 ÷ 190
= 46 min

Time that Eva's cousin left the boutique:
46 min before 6 a.m. = 5.14 a.m.

Answer(s): 5.14 a.m.