Hazel started jogging from the mall to the park at a speed of 100 m/min at 9 a.m. Her sister started jogging from the mall later. They were beside each other at 9.36 a.m. and her sister reached the park at 10 a.m. while Hazel was still 1200 m away. If both of them travelled at a constant speed throughout the journey, what time did her sister leave the mall?
1 h = 60 min

From 9 a.m. to 10 a.m. = 1 h
From 9.36 a.m. to 10 a.m. = 24 min

Distance between the mall and the park
= 60 x 100 + 1200
= 6000 + 1200
= 7200 m

Distance that Hazel's sister had to cover to catch up with Hazel
= 36 x 100
= 3600 m

Distance that Hazel's sister travelled to the park after catching up with Hazel
= 7200 - 3600
= 3600 m

Since Hazel's sister jogged 3600 m in 36 min,
Hazel's sister average speed
= 3600 ÷ 24
= 150 m/min

Duration that Hazel's sister took to jog to the park
= 7200 ÷ 150
= 48 min

Time that Hazel's sister left the mall:
48 min before 10 a.m. = 9.12 a.m.

Answer(s): 9.12 a.m.