Kimberly started jogging from the salon to the garden at a speed of 105 m/min at 8 a.m. Her sister started jogging from the salon later. They were beside each other at 8.41 a.m. and her sister reached the garden at 9 a.m. while Kimberly was still 1900 m away. If both of them travelled at a constant speed throughout the journey, what time did her sister leave the salon?
1 h = 60 min

From 8 a.m. to 9 a.m. = 1 h
From 8.41 a.m. to 9 a.m. = 19 min

Distance between the salon and the garden
= 60 x 105 + 1900
= 6300 + 1900
= 8200 m

Distance that Kimberly's sister had to cover to catch up with Kimberly
= 41 x 105
= 4305 m

Distance that Kimberly's sister travelled to the garden after catching up with Kimberly
= 8200 - 4305
= 3895 m

Since Kimberly's sister jogged 3895 m in 41 min,
Kimberly's sister average speed
= 3895 ÷ 19
= 205 m/min

Duration that Kimberly's sister took to jog to the garden
= 8200 ÷ 205
= 40 min

Time that Kimberly's sister left the salon:
40 min before 9 a.m. = 8.20 a.m.

Answer(s): 8.20 a.m.