Kathy started jogging from the bakery to the garden at a speed of 108 m/min at 6 a.m. Her sister started jogging from the bakery later. They were beside each other at 6.35 a.m. and her sister reached the garden at 7 a.m. while Kathy was still 1800 m away. If both of them travelled at a constant speed throughout the journey, what time did her sister leave the bakery?
1 h = 60 min

From 6 a.m. to 7 a.m. = 1 h
From 6.35 a.m. to 7 a.m. = 25 min

Distance between the bakery and the garden
= 60 x 108 + 1800
= 6480 + 1800
= 8280 m

Distance that Kathy's sister had to cover to catch up with Kathy
= 35 x 108
= 3780 m

Distance that Kathy's sister travelled to the garden after catching up with Kathy
= 8280 - 3780
= 4500 m

Since Kathy's sister jogged 4500 m in 35 min,
Kathy's sister average speed
= 4500 ÷ 25
= 180 m/min

Duration that Kathy's sister took to jog to the garden
= 8280 ÷ 180
= 46 min

Time that Kathy's sister left the bakery:
46 min before 7 a.m. = 6.14 a.m.

Answer(s): 6.14 a.m.