Yoko started jogging from the temple to the garden at a speed of 108 m/min at 9 a.m. Her cousin started jogging from the temple later. They were beside each other at 9.35 a.m. and her cousin reached the garden at 10 a.m. while Yoko was still 1800 m away. If both of them travelled at a constant speed throughout the journey, what time did her cousin leave the temple?
1 h = 60 min

From 9 a.m. to 10 a.m. = 1 h
From 9.35 a.m. to 10 a.m. = 25 min

Distance between the temple and the garden
= 60 x 108 + 1800
= 6480 + 1800
= 8280 m

Distance that Yoko's cousin had to cover to catch up with Yoko
= 35 x 108
= 3780 m

Distance that Yoko's cousin travelled to the garden after catching up with Yoko
= 8280 - 3780
= 4500 m

Since Yoko's cousin jogged 4500 m in 35 min,
Yoko's cousin average speed
= 4500 ÷ 25
= 180 m/min

Duration that Yoko's cousin took to jog to the garden
= 8280 ÷ 180
= 46 min

Time that Yoko's cousin left the temple:
46 min before 10 a.m. = 9.14 a.m.

Answer(s): 9.14 a.m.