Sarah started jogging from the bank to the park at a speed of 100 m/min at 6 a.m. Her sister started jogging from the bank later. They were beside each other at 6.36 a.m. and her sister reached the park at 7 a.m. while Sarah was still 1200 m away. If both of them travelled at a constant speed throughout the journey, what time did her sister leave the bank?
1 h = 60 min

From 6 a.m. to 7 a.m. = 1 h
From 6.36 a.m. to 7 a.m. = 24 min

Distance between the bank and the park
= 60 x 100 + 1200
= 6000 + 1200
= 7200 m

Distance that Sarah's sister had to cover to catch up with Sarah
= 36 x 100
= 3600 m

Distance that Sarah's sister travelled to the park after catching up with Sarah
= 7200 - 3600
= 3600 m

Since Sarah's sister jogged 3600 m in 36 min,
Sarah's sister average speed
= 3600 ÷ 24
= 150 m/min

Duration that Sarah's sister took to jog to the park
= 7200 ÷ 150
= 48 min

Time that Sarah's sister left the bank:
48 min before 7 a.m. = 6.12 a.m.

Answer(s): 6.12 a.m.