A church and a flower shop, 500 m apart, are situated between Fanny's house and Yoko's house. The flower shop is halfway between the two houses
and the church is closer to Yoko's house. Fanny and Yoko left their homes at the same time and arrived at the church at the same time. Fanny drove at a speed of 70 km/h while Yoko drove at a speed 10 km/h slower than Fanny. Leaving your answer in kilometres,
- how much farther did Fanny travel than Yoko?
- how far is Yoko's house from the flower shop?
(a)
Let the distance between Fanny's house and Yoko's house be 1 d.
Yoko travelled =
12 d - 500 m
Fanny travelled =
12 d + 500 m
Distance that Fanny travelled more than Yoko
=
12 d + 500 - (
12 d - 500)
=
12 d + 500 -
12 d + 500
= 1000 m
= 1 km
(b)
Time that Fanny took to travel to the church
= 1 ÷ 10
=
110 h
Distance that Fanny travelled
=
110 x 70
= 7 km
1000 m = 1 km
500 m = 0.5 km
Distance between Yoko's house and the flower shop
= 7 - 0.5
= 6.5 km
Answer(s): (a) 1 km; (b) 6.5 km