A pharmacy and a bank, 500 m apart, are situated between Min's house and Linda's house. The bank is halfway between the two houses
and the pharmacy is closer to Linda's house. Min and Linda left their homes at the same time and arrived at the pharmacy at the same time. Min drove at a speed of 63 km/h while Linda drove at a speed 20 km/h slower than Min. Leaving your answer in kilometres,
- how much farther did Min travel than Linda?
- how far is Linda's house from the bank?
(a)
Let the distance between Min's house and Linda's house be 1 d.
Linda travelled =
12 d - 500 m
Min travelled =
12 d + 500 m
Distance that Min travelled more than Linda
=
12 d + 500 - (
12 d - 500)
=
12 d + 500 -
12 d + 500
= 1000 m
= 1 km
(b)
Time that Min took to travel to the pharmacy
= 1 ÷ 20
=
120 h
Distance that Min travelled
=
120 x 63
= 3.15 km
1000 m = 1 km
500 m = 0.5 km
Distance between Linda's house and the bank
= 3.15 - 0.5
= 2.65 km
Answer(s): (a) 1 km; (b) 2.65 km