A pastry shop and a flower shop, 3500 m apart, are situated between Jean's house and Jaslyn's house. The flower shop is halfway between the two houses
and the pastry shop is closer to Jaslyn's house. Jean and Jaslyn left their homes at the same time and arrived at the pastry shop at the same time. Jean drove at a speed of 66 km/h while Jaslyn drove at a speed 20 km/h slower than Jean. Leaving your answer in kilometres,
- how much farther did Jean travel than Jaslyn?
- how far is Jaslyn's house from the flower shop?
(a)
Let the distance between Jean's house and Jaslyn's house be 1 d.
Jaslyn travelled =
12 d - 3500 m
Jean travelled =
12 d + 3500 m
Distance that Jean travelled more than Jaslyn
=
12 d + 3500 - (
12 d - 3500)
=
12 d + 3500 -
12 d + 3500
= 7000 m
= 7 km
(b)
Time that Jean took to travel to the pastry shop
= 7 ÷ 20
=
720 h
Distance that Jean travelled
=
720 x 66
= 23.1 km
1000 m = 1 km
3500 m = 3.5 km
Distance between Jaslyn's house and the flower shop
= 23.1 - 3.5
= 19.6 km
Answer(s): (a) 7 km; (b) 19.6 km