A salon and a cafe, 1500 m apart, are situated between Jaslyn's house and Tina's house. The cafe is halfway between the two houses
and the salon is closer to Tina's house. Jaslyn and Tina left their homes at the same time and arrived at the salon at the same time. Jaslyn drove at a speed of 60 km/h while Tina drove at a speed 20 km/h slower than Jaslyn. Leaving your answer in kilometres,
- how much farther did Jaslyn travel than Tina?
- how far is Tina's house from the cafe?
(a)
Let the distance between Jaslyn's house and Tina's house be 1 d.
Tina travelled =
12 d - 1500 m
Jaslyn travelled =
12 d + 1500 m
Distance that Jaslyn travelled more than Tina
=
12 d + 1500 - (
12 d - 1500)
=
12 d + 1500 -
12 d + 1500
= 3000 m
= 3 km
(b)
Time that Jaslyn took to travel to the salon
= 3 ÷ 20
=
320 h
Distance that Jaslyn travelled
=
320 x 60
= 9 km
1000 m = 1 km
1500 m = 1.5 km
Distance between Tina's house and the cafe
= 9 - 1.5
= 7.5 km
Answer(s): (a) 3 km; (b) 7.5 km