A church and a flower shop, 2000 m apart, are situated between Fanny's house and Tammy's house. The flower shop is halfway between the two houses and the church is closer to Tammy's house. Fanny and Tammy left their homes at the same time and arrived at the church at the same time. Fanny drove at a speed of 63 km/h while Tammy drove at a speed 15 km/h slower than Fanny. Leaving your answer in kilometres,

1. how much farther did Fanny travel than Tammy?
2. how far is Tammy's house from the flower shop?

(a)
Let the distance between Fanny's house and Tammy's house be 1 d.
Tammy travelled = ¹₂ d - 2000 m
Fanny travelled = ¹₂ d + 2000 m

Distance that Fanny travelled more than Tammy
= ¹₂ d + 2000 - (¹₂ d - 2000)
= ¹₂ d + 2000 - ¹₂ d + 2000
= 4000 m
= 4 km

(b)
Time that Fanny took to travel to the church
= 4 ÷ 15
= ⁴₁₅ h

Distance that Fanny travelled
= ⁴₁₅ x 63
= 16.8 km

1000 m = 1 km
2000 m = 2 km

Distance between Tammy's house and the flower shop
= 16.8 - 2
= 14.8 km

Answer(s): (a) 4 km; (b) 14.8 km