A church and a flower shop, 1500 m apart, are situated between Min's house and Penelope's house. The flower shop is halfway between the two houses and the church is closer to Penelope's house. Min and Penelope left their homes at the same time and arrived at the church at the same time. Min drove at a speed of 70 km/h while Penelope drove at a speed 20 km/h slower than Min. Leaving your answer in kilometres,

1. how much farther did Min travel than Penelope?
2. how far is Penelope's house from the flower shop?

(a)
Let the distance between Min's house and Penelope's house be 1 d.
Penelope travelled = ¹₂ d - 1500 m
Min travelled = ¹₂ d + 1500 m

Distance that Min travelled more than Penelope
= ¹₂ d + 1500 - (¹₂ d - 1500)
= ¹₂ d + 1500 - ¹₂ d + 1500
= 3000 m
= 3 km

(b)
Time that Min took to travel to the church
= 3 ÷ 20
= ³₂₀ h

Distance that Min travelled
= ³₂₀ x 70
= 10.5 km

1000 m = 1 km
1500 m = 1.5 km

Distance between Penelope's house and the flower shop
= 10.5 - 1.5
= 9 km

Answer(s): (a) 3 km; (b) 9 km