The distance between Town S and Town T was 119 km. At 06 00, Nicole left Town S and cycled towards Town T. Jean left Town S and cycled towards Town T at 06 30. Jean's cycling speed was 2 km/h faster than Nicole. At 11 00, Jean caught up with Nicole. When Jean was 35 km from Town T, she stopped to wait for Nicole. How far was Nicole from Jean when she stopped to wait for him?
Duration in which Jean cycled for before she caught up with Nicole
= from 06 30 to 11 00
= 4 h 30 min
= 4 ³⁰₆₀ h
= 4 ¹₂ h

Distance that Jean cycled more than Nicole
= 4¹₂ x 2
= ⁹₂ x 2
= 6 km

Nicole's cycling speed
= 6 x 2
= 12 km/h

Jean's cycling speed
= 12 + 2
= 14 km/h

Distance that Jean cycled before she stopped to wait for Nicole
= 119 - 35
= 84 km

Duration that Jean cycled for after she caught up with Nicole and when she stopped to wait for Nicole
= (84 ÷ 14) - 4¹₂
= 6 - 4¹₂
= 1¹₂ h

Distance Nicole was from Jean when she stopped to wait
= 2 x 1¹₂
= 3 km

Answer(s): 3 km