The distance between Town G and Town H was 166 km. At 06 00, Xylia left Town G and cycled towards Town H. Winnie left Town G and cycled towards Town H at 06 40. Winnie's cycling speed was 3 km/h faster than Xylia. At 11 00, Winnie caught up with Xylia. When Winnie was 19 km from Town H, she stopped to wait for Xylia. How far was Xylia from Winnie when she stopped to wait for him?
Duration in which Winnie cycled for before she caught up with Xylia
= from 06 40 to 11 00
= 4 h 20 min
= 4 ²⁰₆₀ h
= 4 ¹₃ h

Distance that Winnie cycled more than Xylia
= 4¹₃ x 3
= ¹³₃ x 3
= 6 km

Xylia's cycling speed
= 6 x 3
= 18 km/h

Winnie's cycling speed
= 18 + 3
= 21 km/h

Distance that Winnie cycled before she stopped to wait for Xylia
= 166 - 19
= 147 km

Duration that Winnie cycled for after she caught up with Xylia and when she stopped to wait for Xylia
= (147 ÷ 21) - 4¹₃
= 7 - 4¹₃
= 2²₃ h

Distance Xylia was from Winnie when she stopped to wait
= 3 x 2²₃
= 8 km

Answer(s): 8 km