The distance between Town E and Town F was 160 km. At 06 00, Jaslyn left Town E and cycled towards Town F. Fanny left Town E and cycled towards Town F at 06 30. Fanny's cycling speed was 4 km/h faster than Jaslyn. At 9 00, Fanny caught up with Jaslyn. When Fanny was 20 km from Town F, she stopped to wait for Jaslyn. How far was Jaslyn from Fanny when she stopped to wait for him?
Duration in which Fanny cycled for before she caught up with Jaslyn
= from 06 30 to 9 00
= 2 h 30 min
= 2 ³⁰₆₀ h
= 2 ¹₂ h

Distance that Fanny cycled more than Jaslyn
= 2¹₂ x 4
= ⁵₂ x 4
= 6 km

Jaslyn's cycling speed
= 6 x 4
= 24 km/h

Fanny's cycling speed
= 24 + 4
= 28 km/h

Distance that Fanny cycled before she stopped to wait for Jaslyn
= 160 - 20
= 140 km

Duration that Fanny cycled for after she caught up with Jaslyn and when she stopped to wait for Jaslyn
= (140 ÷ 28) - 2¹₂
= 5 - 2¹₂
= 2¹₂ h

Distance Jaslyn was from Fanny when she stopped to wait
= 4 x 2¹₂
= 10 km

Answer(s): 10 km