The distance between Town T and Town U was 184 km. At 07 00, Jean left Town T and cycled towards Town U. Usha left Town T and cycled towards Town U at 07 30. Usha's cycling speed was 2 km/h faster than Jean. At 13 00, Usha caught up with Jean. When Usha was 24 km from Town U, she stopped to wait for Jean. How far was Jean from Usha when she stopped to wait for him?
Duration in which Usha cycled for before she caught up with Jean
= from 07 30 to 13 00
= 5 h 30 min
= 5 ³⁰₆₀ h
= 5 ¹₂ h

Distance that Usha cycled more than Jean
= 5¹₂ x 2
= ¹¹₂ x 2
= 7 km

Jean's cycling speed
= 7 x 2
= 14 km/h

Usha's cycling speed
= 14 + 2
= 16 km/h

Distance that Usha cycled before she stopped to wait for Jean
= 184 - 24
= 160 km

Duration that Usha cycled for after she caught up with Jean and when she stopped to wait for Jean
= (160 ÷ 16) - 5¹₂
= 10 - 5¹₂
= 4¹₂ h

Distance Jean was from Usha when she stopped to wait
= 2 x 4¹₂
= 9 km

Answer(s): 9 km