The distance between Town T and Town U was 95 km. At 05 00, Marion left Town T and cycled towards Town U. Xuan left Town T and cycled towards Town U at 05 30. Xuan's cycling speed was 2 km/h faster than Marion. At 9 00, Xuan caught up with Marion. When Xuan was 23 km from Town U, she stopped to wait for Marion. How far was Marion from Xuan when she stopped to wait for him?
Duration in which Xuan cycled for before she caught up with Marion
= from 05 30 to 9 00
= 3 h 30 min
= 3 ³⁰₆₀ h
= 3 ¹₂ h

Distance that Xuan cycled more than Marion
= 3¹₂ x 2
= ⁷₂ x 2
= 5 km

Marion's cycling speed
= 5 x 2
= 10 km/h

Xuan's cycling speed
= 10 + 2
= 12 km/h

Distance that Xuan cycled before she stopped to wait for Marion
= 95 - 23
= 72 km

Duration that Xuan cycled for after she caught up with Marion and when she stopped to wait for Marion
= (72 ÷ 12) - 3¹₂
= 6 - 3¹₂
= 2¹₂ h

Distance Marion was from Xuan when she stopped to wait
= 2 x 2¹₂
= 5 km

Answer(s): 5 km