The distance between Town X and Town Y was 200 km. At 05 00, Shannon left Town X and cycled towards Town Y. Yoko left Town X and cycled towards Town Y at 05 30. Yoko's cycling speed was 4 km/h faster than Shannon. At 10 00, Yoko caught up with Shannon. When Yoko was 32 km from Town Y, she stopped to wait for Shannon. How far was Shannon from Yoko when she stopped to wait for him?
Duration in which Yoko cycled for before she caught up with Shannon
= from 05 30 to 10 00
= 4 h 30 min
= 4 ³⁰₆₀ h
= 4 ¹₂ h

Distance that Yoko cycled more than Shannon
= 4¹₂ x 4
= ⁹₂ x 4
= 5 km

Shannon's cycling speed
= 5 x 4
= 20 km/h

Yoko's cycling speed
= 20 + 4
= 24 km/h

Distance that Yoko cycled before she stopped to wait for Shannon
= 200 - 32
= 168 km

Duration that Yoko cycled for after she caught up with Shannon and when she stopped to wait for Shannon
= (168 ÷ 24) - 4¹₂
= 7 - 4¹₂
= 2¹₂ h

Distance Shannon was from Yoko when she stopped to wait
= 4 x 2¹₂
= 10 km

Answer(s): 10 km