The distance between Town Z and Town A was 159 km. At 05 00, Cathy left Town Z and cycled towards Town A. Tiffany left Town Z and cycled towards Town A at 05 20. Tiffany's cycling speed was 3 km/h faster than Cathy. At 9 00, Tiffany caught up with Cathy. When Tiffany was 33 km from Town A, she stopped to wait for Cathy. How far was Cathy from Tiffany when she stopped to wait for him?
Duration in which Tiffany cycled for before she caught up with Cathy
= from 05 20 to 9 00
= 3 h 40 min
= 3 ⁴⁰₆₀ h
= 3 ²₃ h

Distance that Tiffany cycled more than Cathy
= 3²₃ x 3
= ¹¹₃ x 3
= 5 km

Cathy's cycling speed
= 5 x 3
= 15 km/h

Tiffany's cycling speed
= 15 + 3
= 18 km/h

Distance that Tiffany cycled before she stopped to wait for Cathy
= 159 - 33
= 126 km

Duration that Tiffany cycled for after she caught up with Cathy and when she stopped to wait for Cathy
= (126 ÷ 18) - 3²₃
= 7 - 3²₃
= 3¹₃ h

Distance Cathy was from Tiffany when she stopped to wait
= 3 x 3¹₃
= 10 km

Answer(s): 10 km