The distance between Town F and Town G was 184 km. At 06 00, Betty left Town F and cycled towards Town G. Kimberly left Town F and cycled towards Town G at 06 40. Kimberly's cycling speed was 3 km/h faster than Betty. At 12 00, Kimberly caught up with Betty. When Kimberly was 37 km from Town G, she stopped to wait for Betty. How far was Betty from Kimberly when she stopped to wait for him?
Duration in which Kimberly cycled for before she caught up with Betty
= from 06 40 to 12 00
= 5 h 20 min
= 5 ²⁰₆₀ h
= 5 ¹₃ h

Distance that Kimberly cycled more than Betty
= 5¹₃ x 3
= ¹⁶₃ x 3
= 6 km

Betty's cycling speed
= 6 x 3
= 18 km/h

Kimberly's cycling speed
= 18 + 3
= 21 km/h

Distance that Kimberly cycled before she stopped to wait for Betty
= 184 - 37
= 147 km

Duration that Kimberly cycled for after she caught up with Betty and when she stopped to wait for Betty
= (147 ÷ 21) - 5¹₃
= 7 - 5¹₃
= 1²₃ h

Distance Betty was from Kimberly when she stopped to wait
= 3 x 1²₃
= 5 km

Answer(s): 5 km