The distance between Town R and Town S was 131 km. At 05 00, Olivia left Town R and cycled towards Town S. Min left Town R and cycled towards Town S at 05 20. Min's cycling speed was 3 km/h faster than Olivia. At 10 00, Min caught up with Olivia. When Min was 23 km from Town S, she stopped to wait for Olivia. How far was Olivia from Min when she stopped to wait for him?
Duration in which Min cycled for before she caught up with Olivia
= from 05 20 to 10 00
= 4 h 40 min
= 4 ⁴⁰₆₀ h
= 4 ²₃ h

Distance that Min cycled more than Olivia
= 4²₃ x 3
= ¹⁴₃ x 3
= 5 km

Olivia's cycling speed
= 5 x 3
= 15 km/h

Min's cycling speed
= 15 + 3
= 18 km/h

Distance that Min cycled before she stopped to wait for Olivia
= 131 - 23
= 108 km

Duration that Min cycled for after she caught up with Olivia and when she stopped to wait for Olivia
= (108 ÷ 18) - 4²₃
= 6 - 4²₃
= 1¹₃ h

Distance Olivia was from Min when she stopped to wait
= 3 x 1¹₃
= 4 km

Answer(s): 4 km