The distance between Town T and Town U was 165 km. At 06 00, Winnie left Town T and cycled towards Town U. Usha left Town T and cycled towards Town U at 06 30. Usha's cycling speed was 2 km/h faster than Winnie. At 13 00, Usha caught up with Winnie. When Usha was 39 km from Town U, she stopped to wait for Winnie. How far was Winnie from Usha when she stopped to wait for him?
Duration in which Usha cycled for before she caught up with Winnie
= from 06 30 to 13 00
= 6 h 30 min
= 6 ³⁰₆₀ h
= 6 ¹₂ h

Distance that Usha cycled more than Winnie
= 6¹₂ x 2
= ¹³₂ x 2
= 6 km

Winnie's cycling speed
= 6 x 2
= 12 km/h

Usha's cycling speed
= 12 + 2
= 14 km/h

Distance that Usha cycled before she stopped to wait for Winnie
= 165 - 39
= 126 km

Duration that Usha cycled for after she caught up with Winnie and when she stopped to wait for Winnie
= (126 ÷ 14) - 6¹₂
= 9 - 6¹₂
= 2¹₂ h

Distance Winnie was from Usha when she stopped to wait
= 2 x 2¹₂
= 5 km

Answer(s): 5 km