The distance between Town C and Town D was 188 km. At 05 00, Nora left Town C and cycled towards Town D. Kimberly left Town C and cycled towards Town D at 05 20. Kimberly's cycling speed was 3 km/h faster than Nora. At 9 00, Kimberly caught up with Nora. When Kimberly was 26 km from Town D, she stopped to wait for Nora. How far was Nora from Kimberly when she stopped to wait for him?
Duration in which Kimberly cycled for before she caught up with Nora
= from 05 20 to 9 00
= 3 h 40 min
= 3 ⁴⁰₆₀ h
= 3 ²₃ h

Distance that Kimberly cycled more than Nora
= 3²₃ x 3
= ¹¹₃ x 3
= 5 km

Nora's cycling speed
= 5 x 3
= 15 km/h

Kimberly's cycling speed
= 15 + 3
= 18 km/h

Distance that Kimberly cycled before she stopped to wait for Nora
= 188 - 26
= 162 km

Duration that Kimberly cycled for after she caught up with Nora and when she stopped to wait for Nora
= (162 ÷ 18) - 3²₃
= 9 - 3²₃
= 5¹₃ h

Distance Nora was from Kimberly when she stopped to wait
= 3 x 5¹₃
= 16 km

Answer(s): 16 km