The distance between Town V and Town W was 187 km. At 06 00, Opal left Town V and cycled towards Town W. Kathy left Town V and cycled towards Town W at 06 30. Kathy's cycling speed was 2 km/h faster than Opal. At 10 00, Kathy caught up with Opal. When Kathy was 19 km from Town W, she stopped to wait for Opal. How far was Opal from Kathy when she stopped to wait for him?
Duration in which Kathy cycled for before she caught up with Opal
= from 06 30 to 10 00
= 3 h 30 min
= 3 ³⁰₆₀ h
= 3 ¹₂ h

Distance that Kathy cycled more than Opal
= 3¹₂ x 2
= ⁷₂ x 2
= 6 km

Opal's cycling speed
= 6 x 2
= 12 km/h

Kathy's cycling speed
= 12 + 2
= 14 km/h

Distance that Kathy cycled before she stopped to wait for Opal
= 187 - 19
= 168 km

Duration that Kathy cycled for after she caught up with Opal and when she stopped to wait for Opal
= (168 ÷ 14) - 3¹₂
= 12 - 3¹₂
= 8¹₂ h

Distance Opal was from Kathy when she stopped to wait
= 2 x 8¹₂
= 17 km

Answer(s): 17 km