At 11 a.m., Hazel and Mary raced off together from the starting point of a route. Hazel ran at an average speed of 1 m/s. Mary ran at an average speed of 4 m/s. Upon reaching the end of the route, Mary rested for 3 minutes. She then immediately ran back along the same route at 4 m/s. At 11.40 a.m., Hazel met Mary.
- Find the total distance covered by the two runners when they met each other. Express your answer in km.
- Find the length of the trail in km.
(a)
From 11 a.m. to 11.40 a.m. = 40 min
Duration that Hazel ran = 40 min
Duration that Mary ran = 40 - 3 = 37 min
1 min = 60 s
37 min = 37 x 60 = 2220 s
40 min = 40 x 60 = 2400 s
Distance that Hazel ran
= 1 x 2400
= 2400 m
Distance that Mary ran
= 4 x 2220
= 8880 m
Distance that Hazel and Mary ran
= 2400 + 8880
= 11280 m
1000 m = 1 km
11280 m = 11280 ÷ 1000 = 11.28 km
(b)
Length of the trail
= 11.28 ÷ 2
= 5.64 km
Answer(s): (a) 11.28 km; (b) 5.64 km