At 9 a.m., Cathy and Fanny raced off together from the starting point of a route. Cathy ran at an average speed of 1 m/s. Fanny ran at an average speed of 3 m/s. Upon reaching the end of the route, Fanny rested for 5 minutes. She then immediately ran back along the same route at 3 m/s. At 9.50 a.m., Cathy met Fanny.

1. Find the total distance covered by the two runners when they met each other. Express your answer in km.
2. Find the length of the trail in km.

(a)
From 9 a.m. to 9.50 a.m. = 50 min

Duration that Cathy ran = 50 min
Duration that Fanny ran = 50 -  5 = 45 min

1 min = 60 s

45 min = 45 x 60 = 2700 s
50 min = 50 x 60 = 3000 s

Distance that Cathy ran
= 1 x 3000
= 3000 m

Distance that Fanny ran
= 3 x 2700
= 8100 m

Distance that Cathy and Fanny ran
= 3000 + 8100
= 11100 m

1000 m = 1 km

11100 m = 11100 ÷ 1000 = 11.1 km

(b)
Length of the trail
= 11.1 ÷ 2
= 5.55 km

Answer(s): (a) 11.1 km; (b) 5.55 km