At 7 a.m., Tiffany and Fanny raced off together from the starting point of a track. Tiffany ran at an average speed of 1 m/s. Fanny ran at an average speed of 3 m/s. Upon reaching the end of the track, Fanny rested for 3 minutes. She then immediately ran back along the same route at 3 m/s. At 7.50 a.m., Tiffany met Fanny.

1. Find the total distance covered by the two runners when they met each other. Express your answer in km.
2. Find the length of the trail in km.

(a)
From 7 a.m. to 7.50 a.m. = 50 min

Duration that Tiffany ran = 50 min
Duration that Fanny ran = 50 -  3 = 47 min

1 min = 60 s

47 min = 47 x 60 = 2820 s
50 min = 50 x 60 = 3000 s

Distance that Tiffany ran
= 1 x 3000
= 3000 m

Distance that Fanny ran
= 3 x 2820
= 8460 m

Distance that Tiffany and Fanny ran
= 3000 + 8460
= 11460 m

1000 m = 1 km

11460 m = 11460 ÷ 1000 = 11.46 km

(b)
Length of the trail
= 11.46 ÷ 2
= 5.73 km

Answer(s): (a) 11.46 km; (b) 5.73 km