At 10 a.m., Jean and Kathy raced off together from the starting point of a pathway. Jean ran at an average speed of 1 m/s. Kathy ran at an average speed of 2 m/s. Upon reaching the end of the pathway, Kathy rested for 3 minutes. She then immediately ran back along the same route at 2 m/s. At 10.35 a.m., Jean met Kathy.
- Find the total distance covered by the two runners when they met each other. Express your answer in km.
- Find the length of the trail in km.
(a)
From 10 a.m. to 10.35 a.m. = 35 min
Duration that Jean ran = 35 min
Duration that Kathy ran = 35 - 3 = 32 min
1 min = 60 s
32 min = 32 x 60 = 1920 s
35 min = 35 x 60 = 2100 s
Distance that Jean ran
= 1 x 2100
= 2100 m
Distance that Kathy ran
= 2 x 1920
= 3840 m
Distance that Jean and Kathy ran
= 2100 + 3840
= 5940 m
1000 m = 1 km
5940 m = 5940 ÷ 1000 = 5.94 km
(b)
Length of the trail
= 5.94 ÷ 2
= 2.97 km
Answer(s): (a) 5.94 km; (b) 2.97 km