At 11 a.m., Shannon and Tiffany raced off together from the starting point of a track. Shannon ran at an average speed of 1 m/s. Tiffany ran at an average speed of 3 m/s. Upon reaching the end of the track, Tiffany rested for 6 minutes. She then immediately ran back along the same route at 3 m/s. At 11.45 a.m., Shannon met Tiffany.
- Find the total distance covered by the two runners when they met each other. Express your answer in km.
- Find the length of the trail in km.
(a)
From 11 a.m. to 11.45 a.m. = 45 min
Duration that Shannon ran = 45 min
Duration that Tiffany ran = 45 - 6 = 39 min
1 min = 60 s
39 min = 39 x 60 = 2340 s
45 min = 45 x 60 = 2700 s
Distance that Shannon ran
= 1 x 2700
= 2700 m
Distance that Tiffany ran
= 3 x 2340
= 7020 m
Distance that Shannon and Tiffany ran
= 2700 + 7020
= 9720 m
1000 m = 1 km
9720 m = 9720 ÷ 1000 = 9.72 km
(b)
Length of the trail
= 9.72 ÷ 2
= 4.86 km
Answer(s): (a) 9.72 km; (b) 4.86 km