At 8 a.m., Jade and Xylia raced off together from the starting point of a pathway. Jade ran at an average speed of 2 m/s. Xylia ran at an average speed of 4 m/s. Upon reaching the end of the pathway, Xylia rested for 6 minutes. She then immediately ran back along the same route at 4 m/s. At 8.45 a.m., Jade met Xylia.
- Find the total distance covered by the two runners when they met each other. Express your answer in km.
- Find the length of the trail in km.
(a)
From 8 a.m. to 8.45 a.m. = 45 min
Duration that Jade ran = 45 min
Duration that Xylia ran = 45 - 6 = 39 min
1 min = 60 s
39 min = 39 x 60 = 2340 s
45 min = 45 x 60 = 2700 s
Distance that Jade ran
= 2 x 2700
= 5400 m
Distance that Xylia ran
= 4 x 2340
= 9360 m
Distance that Jade and Xylia ran
= 5400 + 9360
= 14760 m
1000 m = 1 km
14760 m = 14760 ÷ 1000 = 14.76 km
(b)
Length of the trail
= 14.76 ÷ 2
= 7.38 km
Answer(s): (a) 14.76 km; (b) 7.38 km