At 10 a.m., Linda and Tammy raced off together from the starting point of a path. Linda ran at an average speed of 1 m/s. Tammy ran at an average speed of 2 m/s. Upon reaching the end of the path, Tammy rested for 6 minutes. She then immediately ran back along the same route at 2 m/s. At 10.35 a.m., Linda met Tammy.

1. Find the total distance covered by the two runners when they met each other. Express your answer in km.
2. Find the length of the trail in km.

(a)
From 10 a.m. to 10.35 a.m. = 35 min

Duration that Linda ran = 35 min
Duration that Tammy ran = 35 -  6 = 29 min

1 min = 60 s

29 min = 29 x 60 = 1740 s
35 min = 35 x 60 = 2100 s

Distance that Linda ran
= 1 x 2100
= 2100 m

Distance that Tammy ran
= 2 x 1740
= 3480 m

Distance that Linda and Tammy ran
= 2100 + 3480
= 5580 m

1000 m = 1 km

5580 m = 5580 ÷ 1000 = 5.58 km

(b)
Length of the trail
= 5.58 ÷ 2
= 2.79 km

Answer(s): (a) 5.58 km; (b) 2.79 km