At 9 a.m., Jaslyn and Linda raced off together from the starting point of a route. Jaslyn ran at an average speed of 3 m/s. Linda ran at an average speed of 4 m/s. Upon reaching the end of the route, Linda rested for 3 minutes. She then immediately ran back along the same route at 4 m/s. At 9.45 a.m., Jaslyn met Linda.
- Find the total distance covered by the two runners when they met each other. Express your answer in km.
- Find the length of the trail in km.
(a)
From 9 a.m. to 9.45 a.m. = 45 min
Duration that Jaslyn ran = 45 min
Duration that Linda ran = 45 - 3 = 42 min
1 min = 60 s
42 min = 42 x 60 = 2520 s
45 min = 45 x 60 = 2700 s
Distance that Jaslyn ran
= 3 x 2700
= 8100 m
Distance that Linda ran
= 4 x 2520
= 10080 m
Distance that Jaslyn and Linda ran
= 8100 + 10080
= 18180 m
1000 m = 1 km
18180 m = 18180 ÷ 1000 = 18.18 km
(b)
Length of the trail
= 18.18 ÷ 2
= 9.09 km
Answer(s): (a) 18.18 km; (b) 9.09 km