City Y and City Z is 396 km apart. Bobby left City Y for City Z at 10.00 a.m. travelling at an average speed of 66 km/h. Albert left City Y later than Bobby and caught up with him at 1.00 p.m. Albert was travelling at a speed of 108 km/h.
- At what time did Albert leave City Y?
- How much later did Bobby arrive in City Z than Albert? Express your answer in h as a fraction or mixed number.
(a)
From 10.00 a.m. to 1.00 p.m. = 3 h
Distance that Bobby covered when Albert caught up with Bobby
= 3 x 66
= 198 km
Time that Albert took to travel 198 km
= 198 ÷ 108
= 1
56 h
1 h = 60 min
56 h =
56 x 60 = 50 min
1
56 h = 1 h 50 min
Time that Albert left City Y:
1 h 50 min before 1.00 p.m. = 11.10 a.m.
(b)
Remaining distance that they had to cover to reach City Z
= 396 - 198
= 198 km
Duration that Albert had to travel before reaching City Z
= 198 ÷ 108
= 1
56 h
Duration that Bobby had to travel before reaching City Z
= 198 ÷ 66
= 3 h
Duration that Bobby took to arrive later than Albert in City Z
= 3 - 1
56= 1
16 h
Answer(s): (a) 11.10 a.m.; (b) 1
16 h