City K and City L is 390 km apart. Henry left City K for City L at 9.00 a.m. travelling at an average speed of 65 km/h. Tommy left City K later than Henry and caught up with him at 11.00 a.m. Tommy was travelling at a speed of 104 km/h.

1. At what time did Tommy leave City K?
2. How much later did Henry arrive in City L than Tommy? Express your answer in h as a fraction or mixed number.

(a)
From 9.00 a.m. to 11.00 a.m. = 2 h

Distance that Henry covered when Tommy caught up with Henry
= 2 x 65
= 130 km

Time that Tommy took to travel 130 km
= 130 ÷ 104
= 1¹₄ h

1 h = 60 min
¹₄ h = ¹₄ x 60 = 15 min
1¹₄ h = 1 h 15 min

Time that Tommy left City K:
1 h 15 min before 11.00 a.m. = 9.45 a.m.

(b)
Remaining distance that they had to cover to reach City L
= 390 - 130
= 260 km

Duration that Tommy had to travel before reaching City L
= 260 ÷ 104
= 2¹₂ h

Duration that Henry had to travel before reaching City L
= 260 ÷ 65
= 4 h

Duration that Henry took to arrive later than Tommy in City L
= 4 - 2¹₂
= 1¹₂ h

Answer(s): (a) 9.45 a.m.; (b) 1¹₂ h