City D and City E is 476 km apart. Brandon left City D for City E at 8.00 a.m. travelling at an average speed of 68 km/h. Julian left City D later than Brandon and caught up with him at 10.00 a.m. Julian was travelling at a speed of 96 km/h.

1. At what time did Julian leave City D?
2. How much later did Brandon arrive in City E than Julian? Express your answer in h as a fraction or mixed number.

(a)
From 8.00 a.m. to 10.00 a.m. = 2 h

Distance that Brandon covered when Julian caught up with Brandon
= 2 x 68
= 136 km

Time that Julian took to travel 136 km
= 136 ÷ 96
= 1⁵₁₂ h

1 h = 60 min
⁵₁₂ h = ⁵₁₂ x 60 = 25 min
1⁵₁₂ h = 1 h 25 min

Time that Julian left City D:
1 h 25 min before 10.00 a.m. = 8.35 a.m.

(b)
Remaining distance that they had to cover to reach City E
= 476 - 136
= 340 km

Duration that Julian had to travel before reaching City E
= 340 ÷ 96
= 3¹³₂₄ h

Duration that Brandon had to travel before reaching City E
= 340 ÷ 68
= 5 h

Duration that Brandon took to arrive later than Julian in City E
= 5 - 3¹³₂₄
= 1¹¹₂₄ h

Answer(s): (a) 8.35 a.m.; (b) 1¹¹₂₄ h