City H and City J is 455 km apart. Lee left City H for City J at 10.00 a.m. travelling at an average speed of 65 km/h. Andy left City H later than Lee and caught up with him at 12.00 p.m. Andy was travelling at a speed of 104 km/h.

1. At what time did Andy leave City H?
2. How much later did Lee arrive in City J than Andy? Express your answer in h as a fraction or mixed number.

(a)
From 10.00 a.m. to 12.00 p.m. = 2 h

Distance that Lee covered when Andy caught up with Lee
= 2 x 65
= 130 km

Time that Andy took to travel 130 km
= 130 ÷ 104
= 1¹₄ h

1 h = 60 min
¹₄ h = ¹₄ x 60 = 15 min
1¹₄ h = 1 h 15 min

Time that Andy left City H:
1 h 15 min before 12.00 p.m. = 10.45 a.m.

(b)
Remaining distance that they had to cover to reach City J
= 455 - 130
= 325 km

Duration that Andy had to travel before reaching City J
= 325 ÷ 104
= 3¹₈ h

Duration that Lee had to travel before reaching City J
= 325 ÷ 65
= 5 h

Duration that Lee took to arrive later than Andy in City J
= 5 - 3¹₈
= 1⁷₈ h

Answer(s): (a) 10.45 a.m.; (b) 1⁷₈ h