City H and City J is 325 km apart. Pierre left City H for City J at 8.00 a.m. travelling at an average speed of 65 km/h. Ken left City H later than Pierre and caught up with him at 11.00 a.m. Ken was travelling at a speed of 117 km/h.
- At what time did Ken leave City H?
- How much later did Pierre arrive in City J than Ken? Express your answer in h as a fraction or mixed number.
(a)
From 8.00 a.m. to 11.00 a.m. = 3 h
Distance that Pierre covered when Ken caught up with Pierre
= 3 x 65
= 195 km
Time that Ken took to travel 195 km
= 195 ÷ 117
= 1
23 h
1 h = 60 min
23 h =
23 x 60 = 40 min
1
23 h = 1 h 40 min
Time that Ken left City H:
1 h 40 min before 11.00 a.m. = 9.20 a.m.
(b)
Remaining distance that they had to cover to reach City J
= 325 - 195
= 130 km
Duration that Ken had to travel before reaching City J
= 130 ÷ 117
= 1
19 h
Duration that Pierre had to travel before reaching City J
= 130 ÷ 65
= 2 h
Duration that Pierre took to arrive later than Ken in City J
= 2 - 1
19=
89 h
Answer(s): (a) 9.20 a.m.; (b)
89 h