City L and City M is 546 km apart. Lee left City L for City M at 10.00 a.m. travelling at an average speed of 78 km/h. Peter left City L later than Lee and caught up with him at 12.00 p.m. Peter was travelling at a speed of 104 km/h.
- At what time did Peter leave City L?
- How much later did Lee arrive in City M than Peter? Express your answer in h as a fraction or mixed number.
(a)
From 10.00 a.m. to 12.00 p.m. = 2 h
Distance that Lee covered when Peter caught up with Lee
= 2 x 78
= 156 km
Time that Peter took to travel 156 km
= 156 ÷ 104
= 1
12 h
1 h = 60 min
12 h =
12 x 60 = 30 min
1
12 h = 1 h 30 min
Time that Peter left City L:
1 h 30 min before 12.00 p.m. = 10.30 a.m.
(b)
Remaining distance that they had to cover to reach City M
= 546 - 156
= 390 km
Duration that Peter had to travel before reaching City M
= 390 ÷ 104
= 3
34 h
Duration that Lee had to travel before reaching City M
= 390 ÷ 78
= 5 h
Duration that Lee took to arrive later than Peter in City M
= 5 - 3
34= 1
14 h
Answer(s): (a) 10.30 a.m.; (b) 1
14 h
