City E and City F is 434 km apart. Oliver left City E for City F at 10.00 a.m. travelling at an average speed of 62 km/h. Michael left City E later than Oliver and caught up with him at 2.00 p.m. Michael was travelling at a speed of 96 km/h.

1. At what time did Michael leave City E?
2. How much later did Oliver arrive in City F than Michael? Express your answer in h as a fraction or mixed number.

(a)
From 10.00 a.m. to 2.00 p.m. = 4 h

Distance that Oliver covered when Michael caught up with Oliver
= 4 x 62
= 248 km

Time that Michael took to travel 248 km
= 248 ÷ 96
= 2⁷₁₂ h

1 h = 60 min
⁷₁₂ h = ⁷₁₂ x 60 = 35 min
2⁷₁₂ h = 2 h 35 min

Time that Michael left City E:
2 h 35 min before 2.00 p.m. = 11.25 a.m.

(b)
Remaining distance that they had to cover to reach City F
= 434 - 248
= 186 km

Duration that Michael had to travel before reaching City F
= 186 ÷ 96
= 1¹⁵₁₆ h

Duration that Oliver had to travel before reaching City F
= 186 ÷ 62
= 3 h

Duration that Oliver took to arrive later than Michael in City F
= 3 - 1¹⁵₁₆
= 1¹₁₆ h

Answer(s): (a) 11.25 a.m.; (b) 1¹₁₆ h