City T and City U is 288 km apart. Simon left City T for City U at 11.00 a.m. travelling at an average speed of 72 km/h. Dylan left City T later than Simon and caught up with him at 1.00 p.m. Dylan was travelling at a speed of 108 km/h.
- At what time did Dylan leave City T?
- How much later did Simon arrive in City U than Dylan? Express your answer in h as a fraction or mixed number.
(a)
From 11.00 a.m. to 1.00 p.m. = 2 h
Distance that Simon covered when Dylan caught up with Simon
= 2 x 72
= 144 km
Time that Dylan took to travel 144 km
= 144 ÷ 108
= 1
13 h
1 h = 60 min
13 h =
13 x 60 = 20 min
1
13 h = 1 h 20 min
Time that Dylan left City T:
1 h 20 min before 1.00 p.m. = 11.40 a.m.
(b)
Remaining distance that they had to cover to reach City U
= 288 - 144
= 144 km
Duration that Dylan had to travel before reaching City U
= 144 ÷ 108
= 1
13 h
Duration that Simon had to travel before reaching City U
= 144 ÷ 72
= 2 h
Duration that Simon took to arrive later than Dylan in City U
= 2 - 1
13=
23 h
Answer(s): (a) 11.40 a.m.; (b)
23 h