City K and City L is 310 km apart. Wesley left City K for City L at 10.00 a.m. travelling at an average speed of 62 km/h. Eric left City K later than Wesley and caught up with him at 12.00 p.m. Eric was travelling at a speed of 93 km/h.

1. At what time did Eric leave City K?
2. How much later did Wesley arrive in City L than Eric? Express your answer in h as a fraction or mixed number.

(a)
From 10.00 a.m. to 12.00 p.m. = 2 h

Distance that Wesley covered when Eric caught up with Wesley
= 2 x 62
= 124 km

Time that Eric took to travel 124 km
= 124 ÷ 93
= 1¹₃ h

1 h = 60 min
¹₃ h = ¹₃ x 60 = 20 min
1¹₃ h = 1 h 20 min

Time that Eric left City K:
1 h 20 min before 12.00 p.m. = 10.40 a.m.

(b)
Remaining distance that they had to cover to reach City L
= 310 - 124
= 186 km

Duration that Eric had to travel before reaching City L
= 186 ÷ 93
= 2 h

Duration that Wesley had to travel before reaching City L
= 186 ÷ 62
= 3 h

Duration that Wesley took to arrive later than Eric in City L
= 3 - 2
= 1 h

Answer(s): (a) 10.40 a.m.; (b) 1 h