City K and City L is 360 km apart. Gabriel left City K for City L at 10.00 a.m. travelling at an average speed of 60 km/h. Caden left City K later than Gabriel and caught up with him at 12.00 p.m. Caden was travelling at a speed of 96 km/h.

1. At what time did Caden leave City K?
2. How much later did Gabriel arrive in City L than Caden? Express your answer in h as a fraction or mixed number.

(a)
From 10.00 a.m. to 12.00 p.m. = 2 h

Distance that Gabriel covered when Caden caught up with Gabriel
= 2 x 60
= 120 km

Time that Caden took to travel 120 km
= 120 ÷ 96
= 1¹₄ h

1 h = 60 min
¹₄ h = ¹₄ x 60 = 15 min
1¹₄ h = 1 h 15 min

Time that Caden left City K:
1 h 15 min before 12.00 p.m. = 10.45 a.m.

(b)
Remaining distance that they had to cover to reach City L
= 360 - 120
= 240 km

Duration that Caden had to travel before reaching City L
= 240 ÷ 96
= 2¹₂ h

Duration that Gabriel had to travel before reaching City L
= 240 ÷ 60
= 4 h

Duration that Gabriel took to arrive later than Caden in City L
= 4 - 2¹₂
= 1¹₂ h

Answer(s): (a) 10.45 a.m.; (b) 1¹₂ h