City K and City L is 552 km apart. Wesley left City K for City L at 10.00 a.m. travelling at an average speed of 69 km/h. Will left City K later than Wesley and caught up with him at 1.00 p.m. Will was travelling at a speed of 108 km/h.

1. At what time did Will leave City K?
2. How much later did Wesley arrive in City L than Will? Express your answer in h as a fraction or mixed number.

(a)
From 10.00 a.m. to 1.00 p.m. = 3 h

Distance that Wesley covered when Will caught up with Wesley
= 3 x 69
= 207 km

Time that Will took to travel 207 km
= 207 ÷ 108
= 1¹¹₁₂ h

1 h = 60 min
¹¹₁₂ h = ¹¹₁₂ x 60 = 55 min
1¹¹₁₂ h = 1 h 55 min

Time that Will left City K:
1 h 55 min before 1.00 p.m. = 11.05 a.m.

(b)
Remaining distance that they had to cover to reach City L
= 552 - 207
= 345 km

Duration that Will had to travel before reaching City L
= 345 ÷ 108
= 3⁷₃₆ h

Duration that Wesley had to travel before reaching City L
= 345 ÷ 69
= 5 h

Duration that Wesley took to arrive later than Will in City L
= 5 - 3⁷₃₆
= 1²⁹₃₆ h

Answer(s): (a) 11.05 a.m.; (b) 1²⁹₃₆ h