City D and City E is 540 km apart. Tim left City D for City E at 11.00 a.m. travelling at an average speed of 60 km/h. Ben left City D later than Tim and caught up with him at 3.00 p.m. Ben was travelling at a speed of 90 km/h.
- At what time did Ben leave City D?
- How much later did Tim arrive in City E than Ben? Express your answer in h as a fraction or mixed number.
(a)
From 11.00 a.m. to 3.00 p.m. = 4 h
Distance that Tim covered when Ben caught up with Tim
= 4 x 60
= 240 km
Time that Ben took to travel 240 km
= 240 ÷ 90
= 2
23 h
1 h = 60 min
23 h =
23 x 60 = 40 min
2
23 h = 2 h 40 min
Time that Ben left City D:
2 h 40 min before 3.00 p.m. = 12.20 p.m.
(b)
Remaining distance that they had to cover to reach City E
= 540 - 240
= 300 km
Duration that Ben had to travel before reaching City E
= 300 ÷ 90
= 3
13 h
Duration that Tim had to travel before reaching City E
= 300 ÷ 60
= 5 h
Duration that Tim took to arrive later than Ben in City E
= 5 - 3
13= 1
23 h
Answer(s): (a) 12.20 p.m.; (b) 1
23 h
