City N and City P is 420 km apart. Will left City N for City P at 11.00 a.m. travelling at an average speed of 70 km/h. Brandon left City N later than Will and caught up with him at 1.00 p.m. Brandon was travelling at a speed of 105 km/h.
- At what time did Brandon leave City N?
- How much later did Will arrive in City P than Brandon? Express your answer in h as a fraction or mixed number.
(a)
From 11.00 a.m. to 1.00 p.m. = 2 h
Distance that Will covered when Brandon caught up with Will
= 2 x 70
= 140 km
Time that Brandon took to travel 140 km
= 140 ÷ 105
= 1
13 h
1 h = 60 min
13 h =
13 x 60 = 20 min
1
13 h = 1 h 20 min
Time that Brandon left City N:
1 h 20 min before 1.00 p.m. = 11.40 a.m.
(b)
Remaining distance that they had to cover to reach City P
= 420 - 140
= 280 km
Duration that Brandon had to travel before reaching City P
= 280 ÷ 105
= 2
23 h
Duration that Will had to travel before reaching City P
= 280 ÷ 70
= 4 h
Duration that Will took to arrive later than Brandon in City P
= 4 - 2
23= 1
13 h
Answer(s): (a) 11.40 a.m.; (b) 1
13 h