City F and City G is 315 km apart. Carl left City F for City G at 10.00 a.m. travelling at an average speed of 63 km/h. Caden left City F later than Carl and caught up with him at 12.00 p.m. Caden was travelling at a speed of 72 km/h.
- At what time did Caden leave City F?
- How much later did Carl arrive in City G than Caden? Express your answer in h as a fraction or mixed number.
(a)
From 10.00 a.m. to 12.00 p.m. = 2 h
Distance that Carl covered when Caden caught up with Carl
= 2 x 63
= 126 km
Time that Caden took to travel 126 km
= 126 ÷ 72
= 1
34 h
1 h = 60 min
34 h =
34 x 60 = 45 min
1
34 h = 1 h 45 min
Time that Caden left City F:
1 h 45 min before 12.00 p.m. = 10.15 a.m.
(b)
Remaining distance that they had to cover to reach City G
= 315 - 126
= 189 km
Duration that Caden had to travel before reaching City G
= 189 ÷ 72
= 2
58 h
Duration that Carl had to travel before reaching City G
= 189 ÷ 63
= 3 h
Duration that Carl took to arrive later than Caden in City G
= 3 - 2
58=
38 h
Answer(s): (a) 10.15 a.m.; (b)
38 h