City T and City U is 396 km apart. Will left City T for City U at 8.00 a.m. travelling at an average speed of 66 km/h. Perry left City T later than Will and caught up with him at 11.00 a.m. Perry was travelling at a speed of 88 km/h.
- At what time did Perry leave City T?
- How much later did Will arrive in City U than Perry? Express your answer in h as a fraction or mixed number.
(a)
From 8.00 a.m. to 11.00 a.m. = 3 h
Distance that Will covered when Perry caught up with Will
= 3 x 66
= 198 km
Time that Perry took to travel 198 km
= 198 ÷ 88
= 2
14 h
1 h = 60 min
14 h =
14 x 60 = 15 min
2
14 h = 2 h 15 min
Time that Perry left City T:
2 h 15 min before 11.00 a.m. = 8.45 a.m.
(b)
Remaining distance that they had to cover to reach City U
= 396 - 198
= 198 km
Duration that Perry had to travel before reaching City U
= 198 ÷ 88
= 2
14 h
Duration that Will had to travel before reaching City U
= 198 ÷ 66
= 3 h
Duration that Will took to arrive later than Perry in City U
= 3 - 2
14=
34 h
Answer(s): (a) 8.45 a.m.; (b)
34 h