City N and City P is 240 km apart. Xavier left City N for City P at 10.00 a.m. travelling at an average speed of 60 km/h. Andy left City N later than Xavier and caught up with him at 12.00 p.m. Andy was travelling at a speed of 80 km/h.
- At what time did Andy leave City N?
- How much later did Xavier arrive in City P than Andy? Express your answer in h as a fraction or mixed number.
(a)
From 10.00 a.m. to 12.00 p.m. = 2 h
Distance that Xavier covered when Andy caught up with Xavier
= 2 x 60
= 120 km
Time that Andy took to travel 120 km
= 120 ÷ 80
= 1
12 h
1 h = 60 min
12 h =
12 x 60 = 30 min
1
12 h = 1 h 30 min
Time that Andy left City N:
1 h 30 min before 12.00 p.m. = 10.30 a.m.
(b)
Remaining distance that they had to cover to reach City P
= 240 - 120
= 120 km
Duration that Andy had to travel before reaching City P
= 120 ÷ 80
= 1
12 h
Duration that Xavier had to travel before reaching City P
= 120 ÷ 60
= 2 h
Duration that Xavier took to arrive later than Andy in City P
= 2 - 1
12=
12 h
Answer(s): (a) 10.30 a.m.; (b)
12 h